An electric heating coil rated at 1KW is used to heat 2kg of water for 2 minutes. The initial water temperature is 30o o C. Taking the specific heat of the ...

An electric heating coil rated at 1KW is used to heat 2kg of water for 2 minutes. The initial water temperature is 30${}^o$C. Taking the specific heat of the water as 4,000Jkg ${}^{-1}$ and neglecting that of the container, the final water temperature is

Answer Details

To determine the final temperature of the water, we can use the formula: Q = mcΔT where Q is the heat transferred, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature. We know that the power of the electric heating coil is 1KW, which means it transfers 1000 Joules of energy per second. In 2 minutes, or 120 seconds, it transfers 120,000 Joules of energy to the water. The mass of the water is given as 2kg and the specific heat capacity of water is 4000 J/kg°C. We can assume that the initial temperature of the water is 30°C. Using the formula, we can solve for the change in temperature: 120,000 J = (2 kg)(4000 J/kg°C)(ΔT) ΔT = 15°C Therefore, the final temperature of the water is 30°C + 15°C = 45°C. So, the final water temperature is 45.0oC.