Consider the reaction represented by the equation: 2NaHCO3 → Na2CO 3 + H 2O + CO 2. What is the mass of sodium trioxocarbonate (lV) produced by the complete...

Answer Details

The balanced equation for the reaction shows that 2 moles of NaHCO₃ produce 1 mole of Na₂CO₃, and the molar mass of NaHCO₃ is 84 g/mol. Therefore, 84 g of NaHCO₃ will produce 106 g of Na₂CO₃. To determine the mass of Na₂CO₃ produced from 33.6 g of NaHCO₃, we need to use stoichiometry. 33.6 g NaHCO₃ x (1 mol NaHCO₃ / 84 g NaHCO₃) x (1 mol Na₂CO₃ / 2 mol NaHCO₃) x (106 g Na₂CO₃ / 1 mol Na₂CO₃) = 21.2 g Na₂CO₃ Therefore, the mass of sodium trioxocarbonate (lV) produced by the complete decomposition of 33.6 g of sodium hydrogen trioxocarbonate (IV) is 21.2 g. The correct answer is 21.2 g.