Consider the reaction represented by the equation: 2NaHCO3 → Na2CO 3 + H 2O + CO 2. What is the mass of sodium trioxocarbonate (lV) produced by the complete...
Question 1 Report
Consider the reaction represented by the equation: 2NaHCO3 → Na2CO 3 + H 2O + CO 2. What is the mass of sodium trioxocarbonate (lV) produced by the complete decomposition of 33.6 g of sodium hydrogen trioxocarbonate (IV)? [NaHCO3 = 84, Na2CO3 = 106]
Answer Details
The balanced equation for the reaction shows that 2 moles of NaHCO3 produce 1 mole of Na2CO3, and the molar mass of NaHCO3 is 84 g/mol. Therefore, 84 g of NaHCO3 will produce 106 g of Na2CO3. To determine the mass of Na2CO3 produced from 33.6 g of NaHCO3, we need to use stoichiometry. 33.6 g NaHCO3 x (1 mol NaHCO3 / 84 g NaHCO3) x (1 mol Na2CO3 / 2 mol NaHCO3) x (106 g Na2CO3 / 1 mol Na2CO3) = 21.2 g Na2CO3 Therefore, the mass of sodium trioxocarbonate (lV) produced by the complete decomposition of 33.6 g of sodium hydrogen trioxocarbonate (IV) is 21.2 g. The correct answer is 21.2 g.
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