A man is four times as old as his son. The difference between their ages is 36 years Find the sum of their ages

Assessment: WAEC SSCE - General Mathematics - 2001 (Objective) Subject: General Mathematics

Question 1 Report

A man is four times as old as his son. The difference between their ages is 36 years Find the sum of their ages
Answer Details
Let the age of the son be x. Then, the age of the man will be 4x (as he is four times as old as his son). The difference in their ages is 36 years, so we have: 4x - x = 36 Simplifying this, we get: 3x = 36 x = 12 So, the age of the son is 12 and the age of the man is 4 times that, which is 48. Therefore, the sum of their ages is: 12 + 48 = 60 years. Hence, the correct option is (c) 60 years.

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