Evaluate \(\frac{x^2 + x - 2}{2x^2 + x -3}\) when x = -1

Evaluate \(\frac{x^2 + x - 2}{2x^2 + x -3}\) when x = -1

Answer Details

Substituting x = -1, we get: \[\frac{(-1)^2 + (-1) - 2}{2(-1)^2 + (-1) - 3}\] \[=\frac{1 - 1 - 2}{2 - 1 - 3}\] \[=\frac{-2}{-2}\] \[=1\] Therefore, the value of the expression is 1 when x = -1. Hence the correct option is (d) 1.