Solve : \(\tan (2x - 15)° - 1 = 0\), for values of x such that \(0° \leq x \leq 360°\).

Assessment: WAEC SSCE - Further Mathematics - 2015 (Essay) Subject: Further Mathematics

Question 1 Report

Solve : \(\tan (2x - 15)° - 1 = 0\), for values of x such that \(0° \leq x \leq 360°\).

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