a force of 16N applied 4.0kg block that is at rest on a smooth, horizontal surface. What is the velocity of the block at t = 5 seconds?

Question 1 Report

a force of 16N applied 4.0kg block that is at rest on a smooth, horizontal surface. What is the velocity of the block at t = 5 seconds?

4ms-1

10ms-1

20ms-1

50ms-1

80ms-1

Answer Details

F = ma

= $\frac{m (u - v)}{t}$

16 = $\frac{4 (v - 0)}{5}$

v = 20ms-1

Read lesson note on Newton’s Laws Of Motion (WAEC)

Newton’s Laws Of Motion

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