If \( \log_{10} 2 = 0.3010 \) and \( \log_{10} 3 = 0.4771 \), eventually without using the logarithm tables, \( \log_{10} 4.5 \)

log10 ${}_{10}$2 = 0.3010 and log10 ${}_{10}$3 = 04771

log104.5=log10 ${}_{10}4.5=lo{g}_{10}$ (3×32 $\frac{3\times 3}{2}$)

log10 ${}_{10}$ 3 + log10 ${}_{10}$ 3 - log10 ${}_{10}$2 = 0.4471 + 0.771 - 0.3010

= 0.6532