In this fiqure, PQ = PR = PS and SRT = 68\(^{o}\). Find QPS

Assessment: JAMB UTME - Mathematics - 2020 Subject: General Mathematics

Question 1 Report

In this fiqure, PQ = PR = PS and SRT = 68\(^{o}\). Find QPS

Answer Details

Since PQRS is quadrilateral

2y + 2x + QPS = 360o o

i.e. (y + x) + QPS = 360o o  

QPS = 360o o  - 2 (y + x)

But x + y + 68o o  = 180o o

There; x + y = 180o o  - 68o o  = 112o o

QPS = 360 - 2(112o o )

= 360o o  - 224 = 136o

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