A projectile is fired with a velocity of 20 ms\(^{-1}\) at an angle of 40° to the horizontal. Determine the components of the velocity of the projectile at ...
Question 1 Report
A projectile is fired with a velocity of 20 ms\(^{-1}\) at an angle of 40° to the horizontal. Determine the components of the velocity of the projectile at its maximum height.
Answer Details
The initial velocity components are \(u_x = u\cos\theta\) (horizontal) and \(u_y = u\sin\theta\) (vertical), with \(u = 20\ \text{m s}^{-1}\), \(\theta = 40^\circ\).
At maximum height the vertical component of velocity is momentarily zero (the projectile stops rising). Only the horizontal component remains, and it is unchanged throughout the flight:
\[ v_x = u\cos\theta = 20 \times \cos 40^\circ = 20 \times 0.766 = 15.3\ \text{m s}^{-1}. \] \[ v_y = 0. \]At maximum height: horizontal component \(\approx 15.3\ \text{m s}^{-1}\), vertical component \(= 0\).
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