Make m the subject of the relation k = \(\f..

Question 1 Report

Make m the subject of the relation k = \(\frac{m - y}{m + 1}\)

m = \(\frac{y + k^2}{k^2 + 1}\)

m = \(\frac{y + k^2}{1 - k^2}\)

m = \(\frac{y - k^2}{k^2 + 1}\)

m = \(\frac{y - k^2}{1 - k^2}\)