Given that x is directly proportional to y and inversely proportional to Z, x = 15 when y = 10 and Z = 4, find the equation connecting x, y and z

Question 1 Report

x = \(\frac{6y}{z}\)

x = \(\frac{12y}{z}\)

x = \(\frac{3y}{z}\)

x = \(\frac{3y}{2z}\)