Question 1 Report
(a) Simplify \(\frac{0.016 \times 0.084}{0.48}\) [Leave your answer in standard form].
(b) Eight wooden poles are to be used for pillars and the lengths of the poles form an Arithmetic Progression (A.P). If the second pole is 2m and the sixth is 5m, give the lengths of the poles, in order.
(a) Multiply out the numerator and divide:
\[ \frac{0.016 \times 0.084}{0.48} = \frac{0.001344}{0.48} = 0.0028. \]In standard form:
\[ 0.0028 = 2.8 \times 10^{-3}. \](b) Let the lengths form an A.P. with first term \(a\) and common difference \(d\).
\[ T_2 = a + d = 2, \qquad T_6 = a + 5d = 5. \]Subtracting: \(4d = 3 \implies d = 0.75\ \text{m}\), and \(a = 2 - 0.75 = 1.25\ \text{m}\).
The eight poles, in order, are:
\[ 1.25,\ 2,\ 2.75,\ 3.5,\ 4.25,\ 5,\ 5.75,\ 6.5 \text{ (all in metres).} \]Everything you need to excel in your exams