Evaluate ∫π00sin2xdx

Evaluate ${\int }_0^{\frac{\pi }{0}}sin2xdx$

Answer Details

${\int }_0^{\frac{\pi }{2}}$sin 2x dx = [-1/2cos 2x + C]${}_0^{\frac{\pi }{2}}$
=[-1/2 cos 2 * π/2 + C] - [-1/2 cos 2 * 0]
= [-1/2 cos π] - [-1/2 cos 0]
= [-1/2x - 1] - [-1/2 * 1]
= 1/2 -(-1/2) = 1/2 + 1/2 = 1