Question 1 Report
Evaluate ∫π00sin2xdx
Answer Details
∫π20 ∫ 0 π 2 sin 2x dx = [-1/2cos 2x + C]π20 0 π 2 =[-1/2 cos 2 * π/2 + C] - [-1/2 cos 2 * 0] = [-1/2 cos π] - [-1/2 cos 0] = [-1/2x - 1] - [-1/2 * 1] = 1/2 -(-1/2) = 1/2 + 1/2 = 1
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