Evaluate $ \int_{0}^{\frac{\pi}{0}} \sin 2x \, dx $

Assessment: JAMB UTME - Mathematics - 2005 Subject: General Mathematics

Question 1 Report

zero

-1/2

-1

Answer Details

$\int_{0}^{\frac{π}{2}}$ sin 2x dx = [-1/2cos 2x + C] $_{0}^{\frac{π}{2}}$
=[-1/2 cos 2 * π/2 + C] - [-1/2 cos 2 * 0]
= [-1/2 cos π] - [-1/2 cos 0]
= [-1/2x - 1] - [-1/2 * 1]
= 1/2 -(-1/2) = 1/2 + 1/2 = 1

Read lesson note on Integration (JAMB)

Integration

View Answer

Evaluate \( \int_{0}^{\frac{\pi}{0}} \sin 2x \, dx \)

Download The App On Google Playstore

Evaluate \( \int_{0}^{\frac{\pi}{0}} \sin 2x \, dx \)

Related Questions

Download The App On Google Playstore