A football is kicked at an angle of 45° to the horizontal over a defense line up with a velocity of 15\(ms^{-1}\). Calculate the magnitudeof horizontal velo...

Answer Details

When a projectile is launched at an angle to the horizontal, its initial velocity can be resolved into two components: a horizontal component and a vertical component. The horizontal component remains constant throughout the projectile's motion, while the vertical component is affected by gravity. At the highest point of the projectile's motion, its vertical velocity is zero, but its horizontal velocity remains the same as its initial horizontal velocity. Therefore, the magnitude of the horizontal velocity of the ball at its highest point is 15\(ms^{-1}\)cos(45°) which is approximately equal to 10.6\(ms^{-1}\). Therefore, the correct option is (c) 10.6\(ms^{-1}\).