Make S the subject of the relation p = s + sm2nr

Question 1 Report

Make S the subject of the relation
p = s + $\frac{s m^{2}}{n r}$

s =

\frac{n r p}{n r + m^{2}}

s = nr +

\frac{m^{2}}{m r p}

s =

\frac{n r p}{m r}

+ m2

s =

\frac{n r p}{n r}

+ m2

Answer Details

p = s +

\frac{s m^{2}}{n r}

p = s + ( 1 +

\frac{m^{2}}{n r}

)
p = s (1 +

\frac{n r + m^{2}}{n r}

)
nr × p = s (nr + m2)
s =

\frac{n r p}{n r + m^{2}}

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