A trough 12.0cm deep is filled with water of refractive index 43 4 3 . By how much would a coin at the bottom of the trough appear to be displaced when view...

A trough 12.0cm deep is filled with water of refractive index $\frac{4}{3}$. By how much would a coin at the bottom of the trough appear to be displaced when viewed vertically from above the water surface?

Answer Details

$\frac{4}{3}$ = $\frac{12}{\text{Apparent depth}}$

Apparent depth = 9cm

Height by which coin is raised = 12 - 9

= 3cm