The quadratic equation whose roots are 1 - √13 13 and 1 + √13 13 is

Question 1 Report

The quadratic equation whose roots are 1 - $\sqrt{13}$ and 1 + $\sqrt{13}$ is

x2 + (1 -

\sqrt{13}

)x + 1 +

\sqrt{13}

= 0

x2 - 2x - 12 = 0

x2 - 2x + 12 = 0

x2 + 12 + 2x2 = 0

Answer Details

1 - $\sqrt{13}$ and 1 + $\sqrt{13}$
Product of roots = (1 - $\sqrt{13}$ ) (1 + $\sqrt{13}$ ) = -12
x2 - (sum of roots) x + (product of roots) = 0
x2 - 2x + 12 = 0

Read lesson note on Quadratic Equations (WAEC)

Quadratic Equations

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