Question 1 Report
Find the equation of the circle centre (2. 3) which passes through the y - intercept of the line 3x - 2y + 6 = 0
First find the y-intercept of \(3x-2y+6=0\): put \(x=0\Rightarrow -2y+6=0\Rightarrow y=3\). The point is \((0,3)\).
The radius is the distance from the centre \((2,3)\) to \((0,3)\):
Equation of the circle:
or \(x^2+y^2-4x-6y+9=0\).
Answer Details
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