Given that \(\sin(5x - 28)^\circ = \cos(3x - 50)^\circ\), \(0x < 90^\circ\) Find the value of \(x\)

Assessment: JAMB UTME - Mathematics - 2018 Subject: General Mathematics

Question 1 Report

Given that \(\sin(5x - 28)^\circ = \cos(3x - 50)^\circ\), \(0x < 90^\circ\)

Find the value of \(x\)

Answer Details
Sin(5x - 28) = Cos(3x - 50)………..i
But Sinα = Cos(90 - α)
So Sin(5x - 28) = Cos(90 - [5x - 28])
Sin(5x - 28) = Cos(90 - 5x + 28)
Sin(5x - 28) = Cos(118 - 5x)………ii
Combining i and ii
Cos(3x - 50) = Cos(118 - 5x)
3x - 50 = 118 - 5x
Collecting the like terms
3x + 5x = 118 + 50
8x = 168
x =  168 8
x = 21

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