Question 1 Report
Given that \(\sin(5x - 28)^\circ = \cos(3x - 50)^\circ\), \(0x < 90^\circ\)
Find the value of \(x\)
Answer Details
Sin(5x - 28) = Cos(3x - 50)………..i But Sinα = Cos(90 - α) So Sin(5x - 28) = Cos(90 - [5x - 28]) Sin(5x - 28) = Cos(90 - 5x + 28) Sin(5x - 28) = Cos(118 - 5x)………ii Combining i and ii Cos(3x - 50) = Cos(118 - 5x) 3x - 50 = 118 - 5x Collecting the like terms 3x + 5x = 118 + 50 8x = 168 x = 1688 168 8 x = 21o
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