om a point R, 300m north of P, a man walks eastward to a place Q which is 600m from P. Find the bearing of P from Q, correct to the nearest degree

om a point R, 300m north of P, a man walks eastward to a place Q which is 600m from P. Find the bearing of P from Q, correct to the nearest degree

Answer Details

$\sin y=\frac{300\text{m}}{600\text{m}}=\frac{1}{2}$
$y={\sin }^{-1}0.5$
$y={30}^{\circ }$
$x={180}^{\circ }+({90}^{\circ }-{30}^{\circ })$
$x={180}^{\circ }+{60}^{\circ }$
$x={240}^{\circ }$