The nth term of a sequence is given 31 - n ..

Question 1 Report

The nth term of a sequence is given 31 - n , find the sum of the first terms of the sequence.

\frac{13}{9}

\frac{1}{3}

\frac{1}{9}

Answer Details

Tn = 31 - n
S3 = 31 - 1 + 31 - 2 + 31 - 3
= 1 + $\frac{1}{3}$ + $\frac{1}{9}$
= $\frac{13}{9}$