Find the value of k if 5+2r(r+1)(r−2) 5 + 2 r ( r + 1 ) ( r − 2 ) expressed in partial fraction is kr−2 k r − 2 + Lr+1 L r + 1 where K and L are constants

Find the value of k if $\frac{5+2r}{(r+1)(r-2)}$ expressed in partial fraction is $\frac{k}{r-2}$ + $\frac{L}{r+1}$ where K and L are constants

Answer Details

5 + 2r = k(r + 1) + L(r - 2)
but r - 2 = 0 and r = 2
9 = 3k
k = 3