Find the range of values of x for which 3x - 7 ≤ 0 and x + 5 > 0
Answer Details
The first inequality 3x - 7 ≤ 0 can be solved as follows:
3x - 7 ≤ 0
3x ≤ 7
x ≤ 7/3
The second inequality x + 5 > 0 can be solved as follows:
x + 5 > 0
x > -5
So the range of values of x that satisfies both inequalities is -5 < x ≤ 7/3.
The correct answer is -5 < x ≤ 7/3.