Question 1 Report
From the diagram above, find the area of the triangle PQR
Answer Details
Area of triangle PQR = \(\frac{1}{2}\) x QR x Pc
Where QR = base of triangle PQR, Pc = height of triangle PQR
Area of triangle PQR = \(\frac{1}{2}\) x 20 x 13 = 10 x 13 = 130cm\(^2\).
Given that a * b = \(\frac{a + b}{\text{ab}}\) + (a - b). Find the value of 3 * 2
Simplify 125\(^{−\frac{1}{3}}\) × 49\(^{−\frac{1}{2}}\) × 10\(^0\)
Solve the simultaneous equation \(\frac{\text{x}}{2}\) - \(\frac{\text{y}}{5}\) = 1 and y - \(\frac{\text{x}}{3}\) = 8
Find the coordinates of the midpoint of line PQ given P(-3, 4) and Q(5, 6).
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Given that Cos A = \(\frac{12}{13}\) for 0 ≤ A ≤ 90º, find Tan A.
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