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If sin θ = \(\frac{\sqrt{3}}{2}\) and 0 < θ < 180°, what is cos θ ?
Question 1
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If sin θ = \(\frac{\sqrt{3}}{2}\) and 0 < θ < 180°, what is cos θ ?
\(\frac{1}{\sqrt{3}}\)
\(\frac{2}{\sqrt{3}}\)
\(\frac{1}{2}\)
\(\frac{\sqrt{3}}{2}\)
\(\sqrt{3}\)
Answer Details
Read lesson note on Sine, Cosine And Tangent Of An Angle (WAEC)
Sine, Cosine And Tangent Of An Angle
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