Question 1 Report
Two classes fund-raise for school sports day by selling wristbands at \(x\) pounds and badges at \(y\) pounds. Class A sells 4 wristbands and 6 badges for £38. Class B sells 7 wristbands and 2 badges for £41.
Scaling the second equation to match the coefficient of \(y\) in the first allows \(y\) to be eliminated by subtraction.
(a) Four wristbands and six badges sell for £38: \(4x + 6y = 38\). [1 mark]
(b) Seven wristbands and two badges sell for £41: \(7x + 2y = 41\). [1 mark]
(c) Multiplying the second equation by 3 gives \(21x + 6y = 123\). Subtracting the first equation eliminates \(y\): \(17x = 85\), so \(x = 5\). Substituting into the second equation, \(7(5) + 2y = 41\), so \(2y = 6\), giving \(y = 3\). One wristband costs £5 and one badge costs £3. [3 marks]
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