A farmer mixes \(3\frac{1}{5}\) tonnes of silage with \(2\frac{3}{10}\) tonnes of hay to make a large batch of winter feed for her herd of cattle. She uses ...
Question 1 Report
A farmer mixes \(3\frac{1}{5}\) tonnes of silage with \(2\frac{3}{10}\) tonnes of hay to make a large batch of winter feed for her herd of cattle. She uses \(1\frac{7}{10}\) tonnes of the mixture during the first week of winter. Work out how many tonnes of the winter feed mixture remain, giving your answer as a mixed number. (4)
Answer Details
This question tests adding two mixed numbers and then subtracting a third. Writing both amounts over the common denominator 10 gives \(3\frac{1}{5} = \frac{32}{10}\) and \(2\frac{3}{10} = \frac{23}{10}\), so the winter feed mixture starts at \(\frac{32}{10} + \frac{23}{10} = \frac{55}{10} = 5\frac{1}{2}\) tonnes [2 marks].
Subtracting the \(1\frac{7}{10}\) tonnes used in the first week, both written in tenths, gives \(\frac{55}{10} - \frac{17}{10} = \frac{38}{10}\) [1 mark]. Simplifying and converting to a mixed number, \(\frac{38}{10} = \frac{19}{5} = 3\frac{4}{5}\) tonnes of the mixture remain [1 mark].
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