The cumulative frequency graph shows the distances jumped, in metres, by 40 competitors in the long jump at a school sports day. 0 5 10 15 20 25 30 35 40 0 ...

Assessment: Mathematics Specification A 4MA1 | Paper 2 Mock 01 | Written Paper 2 (2F/2H) Subject: Mathematics Specification A - 4MA1

Question 1 Report

The cumulative frequency graph shows the distances jumped, in metres, by 40 competitors in the long jump at a school sports day.

0 5 10 15 20 25 30 35 40 0 1 2 3 4 5 6 7 Distance (m) Cumulative frequency © EAGLE BEACON GLOBAL
  1. Use the graph to find the median distance jumped. (1)
  2. Use the graph to find the interquartile range of the distances. (2)
  3. Use the graph to estimate the number of competitors who jumped further than 5.5 m. (1)

Answer Details

This question tests reading the median, the two quartiles and a specific cumulative frequency value directly from a cumulative frequency graph.

(a) With 40 competitors, the median lies at a cumulative frequency of \( 40 \div 2 = 20 \). Reading across from 20 on the vertical axis to the curve, then down to the horizontal axis, gives a median distance of 4.8 m (accept 4.6 to 5.0). [1 mark]

(b) The lower quartile is read at a cumulative frequency of \( 40 \div 4 = 10 \), giving 4.0 m, and the upper quartile is read at \( 3 \times 40 \div 4 = 30 \), giving 5.7 m. The interquartile range is

\[ 5.7 - 4.0 = 1.7 \text{ m (accept 1.5 to 1.9)} \] [2 marks]

(c) Reading up from 5.5 m on the horizontal axis to the curve gives a cumulative frequency of about 28, meaning 28 competitors jumped 5.5 m or less. The number who jumped further than 5.5 m is therefore

\[ 40 - 28 = 12 \text{ competitors (accept 10 to 14)} \] [1 mark]

A cumulative frequency graph always reads "up to and including" a distance, so finding "more than" a value, as in part (c), requires subtracting the reading from the total.

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