A car park bay next to a bus interchange is painted in the shape of a parallelogram, with a base of 4.8 m and a perpendicular height of 2.4 m, as shown in t...
Question 1 Report
A car park bay next to a bus interchange is painted in the shape of a parallelogram, with a base of 4.8 m and a perpendicular height of 2.4 m, as shown in the diagram. The markings must be repainted before the new timetable begins.
Work out the area of the bay. (3)
Answer Details
The car park bay is a parallelogram, so its area is \( \text{base} \times \text{perpendicular height} \), not base times a slanted side.
\[ \text{Area} = 4.8 \times 2.4 = 11.52 \text{ m}^2 \]The area of the bay is \(11.52\) m\(^2\). [3] (1 for identifying base and perpendicular height, 1 for \(4.8 \times 2.4\), 1 for 11.52 m\(^2\))
The dashed line in the diagram marks the perpendicular height, drawn at right angles to the base; the slanted side of the parallelogram is longer than this and must never be substituted into the area formula in its place.
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