A regional bus operator runs two routes and records how many buses arrive on time each week. On Route A, 92% of 650 buses arrived on time. On Route B, 88% o...
Question 1 Report
A regional bus operator runs two routes and records how many buses arrive on time each week. On Route A, 92% of 650 buses arrived on time. On Route B, 88% of 800 buses arrived on time. The operator publishes these punctuality figures every quarter so passengers can see how reliably each route is running.
- Work out how many buses were late on Route A. (2)
- Work out how many buses were late on Route B, and state how many more late buses Route B had than Route A. (3)
Answer Details
This question tests finding a percentage (the complement of an on-time rate) of two different totals and comparing the resulting counts.
- On Route A, \(100\% - 92\% = 8\%\) of buses were late: \(0.08 \times 650 = \) 52 [2].
- On Route B, \(100\% - 88\% = 12\%\) of buses were late: \(0.12 \times 800 = 96\). Route B had \(96 - 52 = \) 44 more late buses than Route A [3].
Find the "late" percentage first by subtracting the on-time percentage from 100%, then apply it to each route's own total; the two routes cannot be compared using the same total, since Route B ran more buses than Route A.
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