Table 1 shows results from a metabolic clinic that tests the DNA of adults before they plan a family. The enzyme is needed to break down a substance found i...

Assessment: Biology 4BI1 | Paper 1 Mock 01 | Written Paper 1 Subject: Biology - 4BI1

Question 1 Report

Table 1 shows results from a metabolic clinic that tests the DNA of adults before they plan a family. The enzyme is needed to break down a substance found in some food. A person with no working copies of the allele produces almost no enzyme and develops the condition. Nia and Omar are both healthy, but their cell tests and DNA results are shown in the table.

GenotypeEnzyme made by cellsHealth status
AAhigh amountunaffected
Aamedium amountunaffected carrier
aavery low amountaffected
Nia: Aamedium amountunaffected carrier
Omar: Aamedium amountunaffected carrier

(a) State the genotype of a child who develops the enzyme condition. [1]

(b) Explain why Nia does not show symptoms of the condition. [2]

(c) Complete a genetic cross for Nia and Omar. Include the gametes, all four possible genotypes of their children and the phenotype ratio. [4]

(d) Calculate the probability that one child of Nia and Omar will be an unaffected carrier. [2]

(e) Suggest why the clinic explains that an affected child is possible even though both parents are healthy. [1]

Answer Details

(a) A child who develops the condition has genotype \(aa\). [1]

(b) \(A\) is the dominant, working allele. Nia has one \(A\) allele, which allows sufficient enzyme to be made, so she does not show symptoms. [2]

(c) Both Nia and Omar are \(Aa\), so each produces \(A\) and \(a\) gametes.

Omar \(A\)Omar \(a\)
Nia \(A\)\(AA\), unaffected\(Aa\), unaffected carrier
Nia \(a\)\(Aa\), unaffected carrier\(aa\), affected

The possible genotypes are \(AA\), \(Aa\), \(Aa\) and \(aa\). The phenotype ratio is \(3\) unaffected : \(1\) affected. [4]

(d) Two of the four possible offspring genotypes are \(Aa\):

\[\frac{2}{4}=\frac{1}{2}=50\%\]

The probability of an unaffected carrier is \(\frac{1}{2}\), or \(50\%\). [2]

(e) Both healthy parents can pass their recessive \(a\) allele to the same child. That child could inherit \(aa\) and be affected. [1]

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