If the heights of two circular cylinder are in the ratio 2 : 3 and their volumes?

If the heights of two circular cylinder are in the ratio 2 : 3 and their volumes?

Answer Details

$\frac{h_1}{h_2}$ = $\frac{2}{3}$
h2 = $\frac{2h_1}{3}$
$\frac{r_1}{r_2}$ = $\frac{9}{8}$
r2 = $\frac{9r_1}{8}$
v1 = $\pi$($\frac{9r_1}{8}$)2($\frac{2h_1}{3}$)
= $\pi$r1 2h1 x $\frac{27}{32}$
v = $\frac{\pi r_{1}2h_1\times \frac{27}{32}}{\pi r_{1}2h_1}$ = $\frac{27}{32}$
v2 : v1 = 27 : 32