Question 1 Report
A certain volume of gas at 298k is heated such that its volume and pressure are now four times the original values. What is the new temperature?
Answer Details
P1V1T1=4P1×4V1T2 P 1 V 1 T 1 = 4 P 1 × 4 V 1 T 2
i.e P1V1298=4P1×4V1T2 P 1 V 1 298 = 4 P 1 × 4 V 1 T 2
T2 = 298×4P1×4V1P1V1 298 × 4 P 1 × 4 V 1 P 1 V 1
= 298 + 16 = 4768.0k