(a) A zinc salt, E when heated strongly, produced a brown gas with pungent smell, a colourless gas that rekindled a glowing splint, and a residue that was a...

Assessment: WAEC SSCE - Chemistry - 2020 (Practical) Subject: Chemistry

Question 1 Report

(a) A zinc salt, E when heated strongly, produced a brown gas with pungent smell, a colourless gas that rekindled a glowing splint, and a residue that was allowed to cool.

(i) identify the salt E.

(ii) Write an equation for the decomposition of E.

(iii) State what would be observed when the residue was allowed to cool.

(b) Describe how 250cm\(^3\) of 0.2 mol dm\(^3\) H\(_2\)SO\(_4\) could be prepared from 150 cm\(^3\) of a 1.0 mol dm\(^{3}\) stock solution of the acid.

(c) State the effect of aqueous solution of Al\(_2(SO_4)_3\) on litmus paper.

 

Answer Details

(a) Identifying the zinc salt E

On strong heating E gives a brown pungent gas (nitrogen(IV) oxide, \(NO_2\)), a colourless gas that rekindles a glowing splint (oxygen, \(O_2\)) and a solid residue. These are the products of thermal decomposition of a zinc nitrate.

  • (i) E is zinc trioxonitrate(V), \(Zn(NO_3)_2\).
  • (ii) Equation for the decomposition:
\[2Zn(NO_3)_{2(s)} \to 2ZnO_{(s)} + 4NO_{2(g)} + O_{2(g)}\]
  • (iii) The residue is zinc oxide, which is yellow while hot but turns white on cooling.

(b) Preparing 250 cm\(^3\) of 0.2 mol dm\(^{-3}\) H2SO4 from a 1.0 mol dm\(^{-3}\) stock

Moles of acid required \(= 0.2 \times \dfrac{250}{1000} = 0.05\,mol\).

Volume of stock needed \(= \dfrac{0.05}{1.0} = 0.05\,dm^3 = 50\,cm^3\).

Procedure: using a pipette or measuring cylinder, measure 50 cm\(^3\) of the 1.0 mol dm\(^{-3}\) stock acid and add it slowly, with stirring, to some distilled water already in a 250 cm\(^3\) volumetric flask (always add acid to water). Then make up the solution to the 250 cm\(^3\) mark with more distilled water, stopper and shake to mix thoroughly. (The 150 cm\(^3\) of stock available is more than the 50 cm\(^3\) required.)

(c) Effect of aluminium tetraoxosulphate(VI) solution on litmus

Aqueous \(Al_2(SO_4)_3\) turns blue litmus red, i.e. the solution is acidic. This is because the salt of a strong acid and a weak base undergoes hydrolysis to give an acidic solution.

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