In a uniform electric field, the magnitude of the force on a charge of 0.2 C is 4N. Calculate the electric field intensity
Question 1 Report
In a uniform electric field, the magnitude of the force on a charge of 0.2 C is 4N. Calculate the electric field intensity
Answer Details
The electric force, F, on a charge, q, in an electric field, E, is given by the formula: F = qE Here, the force, F, is given as 4 N and the charge, q, is 0.2 C. We can rearrange the formula to solve for the electric field intensity, E: E = F/q Substituting the values we have: E = 4 N / 0.2 C E = 20 N C-1 Therefore, the electric field intensity is 20 N C-1, which is closest to 20 N C-1. In simpler terms, the electric field intensity is the force experienced by a unit charge in an electric field. In this case, a charge of 0.2 C experiences a force of 4 N, so the electric field intensity is the force per unit charge, which is 4 N divided by 0.2 C, giving 20 N C-1.
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