An iron rod of length 50m and at a temperature of 60oC is heated to 70oC. Calculate its new length. (Linear expansivity of iron = 1.2 x 10-5K-1)
Question 1 Report
An iron rod of length 50m and at a temperature of 60oC is heated to 70oC. Calculate its new length. (Linear expansivity of iron = 1.2 x 10-5K-1)
Answer Details
The formula for linear thermal expansion is:
ΔL = αLΔT
Where:
ΔL = change in length
α = coefficient of linear expansion
L = original length
ΔT = change in temperature
Using the values given:
L = 50 m
α = 1.2 x 10^-5 K^-1
ΔT = 70°C - 60°C = 10°C
Substituting the values in the formula:
ΔL = (1.2 x 10^-5 K^-1)(50 m)(10°C)
ΔL = 0.006 m
The new length of the iron rod is the sum of the original length and the change in length:
New length = 50 m + 0.006 m = 50.006 m
Therefore, the correct answer is: 50.006m.
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