A point charge of magnitude 2μC is moved through a distance of 0.02 m against uniform field of intensity 25 Vm-1 Calculate the work done on the charge
Question 1 Report
A point charge of magnitude 2μC is moved through a distance of 0.02 m against uniform field of intensity 25 Vm-1 Calculate the work done on the charge
Answer Details
The work done on a point charge moving through a distance against an electric field is given by the formula: W = qEd where: - W is the work done - q is the magnitude of the point charge - E is the intensity of the electric field - d is the distance moved against the electric field In this case, the point charge has a magnitude of 2μC, the electric field has an intensity of 25 Vm-1, and the distance moved against the electric field is 0.02 m. Substituting these values into the formula, we get: W = (2 x 10-6 C) x (25 Vm-1) x (0.02 m) W = 1 x 10-6 J Therefore, the work done on the charge is 1.0 x 10-6J.
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