A body of mass M kg rests on a plane inclined at an angle \(\theta\) to the horizontal. The component of the weight of the body parallel to the plane is

Answer Details

When a body rests on an inclined plane, its weight can be resolved into two components: one perpendicular to the plane, and the other parallel to the plane. The component of weight parallel to the inclined plane is given by Mg sin \(\theta\), where M is the mass of the body, g is the acceleration due to gravity, and \(\theta\) is the angle of inclination. This is because the weight acts vertically downwards and the component parallel to the plane is given by the weight multiplied by the sine of the angle of inclination. So, the correct option is Mg sin \(\theta\).