A charge of 1.6 x 10-10C is placed in a uniform electric field of intensity 2.0 x 105NC-1. What is the magnitude of the electric force exerted on the charge...
Question 1 Report
A charge of 1.6 x 10-10C is placed in a uniform electric field of intensity 2.0 x 105NC-1. What is the magnitude of the electric force exerted on the charge?
Answer Details
The magnitude of the electric force exerted on a charge in a uniform electric field is given by the product of the magnitude of the charge and the electric field strength. Mathematically, F = qE, where F is the force, q is the charge and E is the electric field strength. Substituting the given values, we have: F = (1.6 x 10^-10 C) x (2.0 x 10^5 N/C) = 3.2 x 10^-5 N Therefore, the magnitude of the electric force exerted on the charge is 3.2 x 10^-5 N. Hence, the correct option is (C) 3.2 x10-5N.
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