Calculate the electric potential at a distance of 20.0cm from a point charge of 0.015C placed in air of permittivity (Take 1/4πεo as 9.0 x 109 Nm2C2)

Assessment: WAEC SSCE - Physics - 1995 (Objective) Subject: Physics

Question 1 Report

Calculate the electric potential at a distance of 20.0cm from a point charge of 0.015C placed in air of permittivity (Take 1/4πε_o as 9.0 x 10⁹ Nm²C²)

3.40x10⁶V

6.75x10⁵V

6.75x10¹²V

3.40x10⁵V

8.30 x 10²V

Answer Details

The electric potential at a point due to a point charge is given by the formula: V = kQ/r where V is the potential, Q is the charge, r is the distance of the point from the charge, and k is Coulomb's constant, which is equal to 1/4πε_o. In this question, the point charge is 0.015C, the distance from the charge is 20.0cm (which is 0.20m), and the value of k is 9.0 x 10⁹ Nm²C². Substituting these values into the formula: V = (9.0 x 10⁹ Nm²C²) x (0.015C) / (0.20m) V = 6.75 x 10⁵ V Therefore, the electric potential at a distance of 20.0cm from a point charge of 0.015C placed in air of permittivity is 6.75 x 10⁵ V. The answer is.

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Calculate the electric potential at a distance of 20.0cm from a point charge of 0.015C placed in air of permittivity (Take 1/4πεo as 9.0 x 109 Nm2C2)

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