A body weighing 10 N in air is partially immersed in water. It displaces water of mass 0.3 kg. What is the upthrust on the body? (g = 10 ms-2)
Question 1 Report
A body weighing 10 N in air is partially immersed in water. It displaces water of mass 0.3 kg. What is the upthrust on the body? (g = 10 ms-2)
Answer Details
The upthrust on a body is equal to the weight of the fluid displaced by the body. Since the body is partially immersed in water and displaces water of mass 0.3 kg, we can find the volume of water displaced using the density of water, which is 1000 kg/m^3.
Volume of water displaced = Mass of water displaced / Density of water
= 0.3 kg / 1000 kg/m^3
= 0.0003 m^3
The weight of the water displaced is given by the product of its mass and the acceleration due to gravity, g.
Weight of water displaced = Mass of water displaced x g
= 0.3 kg x 10 ms^-2
= 3 N
Therefore, the upthrust on the body is 3 N.
Hence, option D (3.0 N) is the correct answer.
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