An object of mass 0.40 kg attached to the end of a string is whirled around in a horizontal circle of radius 2.0m with a constant speed of 8\(ms^{-1}\). Cal...

Answer Details

The angular velocity of the object can be found using the formula: ω = v/r where ω is the angular velocity, v is the velocity of the object and r is the radius of the circle. In this case, the velocity of the object is given as 8\(ms^{-1}\) and the radius of the circle is given as 2.0m. So, ω = 8\(ms^{-1}\)/2.0m = 4 rad\(s^{-1}\) Therefore, the angular velocity of the object is 4 rad\(s^{-1}\). Hence, the correct option is (c) 4 rad\(s^{-1}\).