A solid plastic cube of side 0.2m is submerged in a liquid density of 0.8kg\(m^{-3}\). Calculate the upthrust of the liquid on the cube (g=10\(ms^{-2}\)

Answer Details

The upthrust on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. The volume of the cube is given by: V = (0.2m) x (0.2m) x (0.2m) = 0.008m³ Since the cube is submerged in a liquid density of 0.8kg\(m^{-3}\), the mass of the fluid displaced by the cube is: m = ρV = 0.8kg\(m^{-3}\) x 0.008m³ = 0.0064kg The weight of the fluid displaced is: W = mg = (0.0064kg) x (10\(ms^{-2}\)) = 0.064N Therefore, the upthrust on the cube is 0.064N. So the correct option is: - 0.064N