A solid plastic cube of side 0.2m is submerged in a liquid density of 0.8kg\(m^{-3}\). Calculate the upthrust of the liquid on the cube (g=10\(ms^{-2}\)
Question 1 Report
A solid plastic cube of side 0.2m is submerged in a liquid density of 0.8kg\(m^{-3}\). Calculate the upthrust of the liquid on the cube (g=10\(ms^{-2}\)
Answer Details
The upthrust on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
The volume of the cube is given by:
V = (0.2m) x (0.2m) x (0.2m) = 0.008m³
Since the cube is submerged in a liquid density of 0.8kg\(m^{-3}\), the mass of the fluid displaced by the cube is:
m = ρV = 0.8kg\(m^{-3}\) x 0.008m³ = 0.0064kg
The weight of the fluid displaced is:
W = mg = (0.0064kg) x (10\(ms^{-2}\)) = 0.064N
Therefore, the upthrust on the cube is 0.064N.
So the correct option is:
- 0.064N
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