When sodium ethanoate is treated with a few drops of concentrated tetraoxosulphate(vi)acid. one of the products is
Answer Details
When sodium ethanoate (also known as sodium acetate) is treated with concentrated tetraoxosulphate (VI) acid (also known as sulfuric acid), one of the products formed is ethanoic acid (CH3COOH). This is due to the fact that the sulfuric acid protonates the acetate ion in the sodium ethanoate solution, leading to the formation of ethanoic acid and sodium sulfate as the other product.
Therefore, the correct option is: CH3COOH.