Make S the subject of the relation p = s + ..

Question 1 Report

Make S the subject of the relation
p = s + $\frac{s m^{2}}{n r}$

s =

\frac{n r p}{n r + m^{2}}

s = nr +

\frac{m^{2}}{m r p}

s =

\frac{n r p}{m r}

+ m2

s =

\frac{n r p}{n r}

+ m2

Answer Details

p = s + $\frac{s m^{2}}{n r}$
p = s + ( 1 + $\frac{m^{2}}{n r}$ )
p = s (1 + $\frac{n r + m^{2}}{n r}$ )
nr × p = s (nr + m2)
s = $\frac{n r p}{n r + m^{2}}$

View Answer

Make S the subject of the relation p = s + sm2nr