Evaluate π2∫0 ∫ 0 π 2 sin xdx

Question 1 Report

Evaluate $\int_{0}^{\frac{π}{2}}$ sin xdx

-1

-2

Answer Details

$\int_{0}^{\frac{π}{2}}$ sin xdx = -cosx| $\frac{π}{2}$
= -(cos $\frac{π}{2}$ - cos0) = -(0-1) = 1