he determination of the matrix ⎛⎜⎝133456201⎞⎟⎠ ( 1 3 3 4 5 6 2 0 1 ) is

he determination of the matrix $\left(\begin{array}{ccc}1& 3& 3\\ 4& 5& 6\\ 2& 0& 1\end{array}\right)$ is

Answer Details

4 x 2 = -8 upward arrows = +ve
2 x 5 x 3 = 30
0 x 6 = $\frac{0}{22}$ downward arrows = -ve
-1(1 x 5x - 1) = 5 - (2 x 6 x 2) = -24
= -(4 x 0 x 1)
= $\frac{0}{-19}$
therefore 22 - 19 = 3