Find P if x?3(1?x)(x+2) x ? 3 ( 1 ? x ) ( x + 2 ) = p1?x p 1 ? x + Qx+2

Find P if $\frac{x?3}{(1?x)(x+2)}$ = $\frac{p}{1?x}$ + $\frac{Q}{x+2}$

Answer Details

$\frac{x-3}{(1-x)(x+2)}$ = $\frac{p}{1-x}$ + $\frac{Q}{x+2}$
Multiply both sides by LCM i.e. (1 - x(x + 2))
∴ x - 3 = p(x + 2) + Q(1 - x)
When x = +1
(+1) - 3 = p(+1 + 2) + Q(1 - 1)
-2 = 3p + 0(Q)
3p = -2
∴ p = $\frac{-2}{3}$