Question 1 Report
Solve for r in the following equation 1r−1 1 r − 1 + 2r+1 2 r + 1 = 3r
Answer Details
1r−1 1 r − 1 + 2r+1 2 r + 1 = 3r 3 r Multiply through by r(r -1) which is the LCM = (r)(r + 1) + 2(r)(r - 1) = 3(r - 1)(r + 1) = r2 + r + 2r2 - 2r 3r2 - 3 = 3r2 r = 3r2 - 3 -r = -3 ∴ r = 3
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