Question 1 Report
Evaluate \( \int_{-1}^{1} (2x + 1)^2 \, dx \)
Answer Details
∫1−1 ∫ − 1 1 (2x + 1)2dx = ∫1−1 ∫ − 1 1 (4x2 + 4x + 1)dx = ∫1−1 ∫ − 1 1 [4x33 4 x 3 3 + 2x2 + c] = [43 4 3 + 3 + c] - [4 + 13 1 3 + c] = 83 8 3 + 3 + -1 - C = 83 8 3 + 2 = 143 14 3 = 423
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